Question

Calcium carbonate, or limestone, is relatively insoluble in water. At 25 °C, only 5.8 mg will dissolve in 1.0 liter of water. What volume of water is needed to dissolve 5.0 g of calcium carbonate?

Answer 1

Answer:

862 L of water.

Explanation:

Its a proporcionality problem.

If 5.8 mg takes a liter, 5000 mg will take x liters, solving for x gives the volume required for solving 5000 mg of calcium carbonate.

5.8 mg-----------1L

5000 mg--------xL

x=5000/5.8

x=862

Answer 2

The volume of water needed to dissolve 5 g (i.e 5000 mg) of the limestone is 862.1 L

We'll begin by converting 5 g to milligrams (mg)

1 g = 1000 mg

Therefore,

5 g = 5 × 1000

5 g = 5000 mg

Finally, we shall determine the volume of water needed to dissolve 5 g (i.e 5000 mg) of the limestone. This can be obtained as follow:

From the question given above,

5.8 mg of limestone dissolved in 1 L of water.

Therefore,

5000 mg of limestone will dissolve in = $\frac{5000}{5.8}$ = 862.1 L of water.

Thus, 862.1 L of water is needed to dissolve 5 g (i.e 5000 mg) of limestone

Learn more: https://brainly.com/question/20307930