Question

Justin Thyme threw a rock straight down off the Verrazano Narrows Bridge in New York City. Calculate the velocity 0.500 s after the rock is thrown with an initial velocity of 14.0 m/s. The roadway of this bridge is 70.0 m above the water.

Answer 1

Answer:

Final speed, v = 39.59 m/s

Explanation:

It is given that, Justin Thyme threw a rock straight down off the Verrazano Narrows Bridge in New York City.

Initial velocity, u = 14 m/s

The roadway of this bridge is 70.0 m above the water, s = 70 m

Time taken, t = 0.5 s

We need to find the final velocity of the rock. From third equation of motion,

$v^2=u^2+2as$

a = g

$v^2=(14)^2+2\times 9.8\times 70$

v = 39.59 m/s

So, the final velocity after 0.5 s is 39.59 m/s. Hence, this is the required solution.