Question

The position of a ball as a function of time is given by x=3.0m+(−5.0m/s)t


What is the position of the ball at 1.0

Answer 1

Answer:

-2.0 m

Explanation:

x = 3.0 m + (-5.0 m/s) t

At t = 1.0 s:

x = 3.0 m + (-5.0 m/s) (1.0 s)

x = 3.0 m − 5.0 m

x = -2.0 m

Answer 2

The position of a ball as a function of time is given by x=3.0m+(−5.0m/s)t . - 2 m is the position of the ball at 1.0

Explanation:

The equation of motion for the position of a ball is given as the function of time. The position of the ball at the given time thus be calculated from the given equation itself by substituting the value, as shown in the following,

Given equation,

$x=3.0 m+\left(-5.0 \frac{m}{s}\right) t$

Simply writing the equation, we get,

$x=3+(-5) t$

Substituting the value, we get

$x = 3+(-5) \times 1 =3-5 = - 2$

Therefore, the ball will be at the position of 2 meters from the ground. Negative sign shown is according to the convention of sign used.