Answer : The molar concentration of ethanol in the undiluted cognac is 8.44 M
Explanation :
Using neutralization law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molar concentration of undiluted cognac = ?
[tex]M_2[/tex] = molar concentration of diluted cognac = 0.0844 M
[tex]V_1[/tex] = volume of undiluted cognac = 5.00 mL = 0.005 L
[tex]V_2[/tex] = volume of diluted cognac = 0.500 L
Now put all the given values in the above law, we get molar concentration of ethanol in the undiluted cognac.
[tex]M_1\times 0.005L=0.0844M\times 0.500L[/tex]
[tex]M_1=8.44M[/tex]
Therefore, the molar concentration of ethanol in the undiluted cognac is 8.44 M