Question

A mass tied to the end of a 1.0 m-long string is swinging back and forth. From its lowest point, the mass moves 4 cm to the right, swings back through its lowest point to stop 4 cm to the left of its lowest point, then swings back to where it started. One complete swing takes about 2 s. If the amplitude of motion is doubled, so the mass swings 8 cm to one side and then the other, the period of the motion will be _____.

Answer 1

Answer:

If the amplitude of motion is doubled, so the mass swings 8 cm to one side and then the other, the period of the motion will be 2 s.

Explanation:

As we know that time period of the motion of the simple pendulum is given as

$T = 2\pi \sqrt{\frac{L}{g}}$

here we know that

L = length of the pendulum

g = acceleration due to gravity

so as per above formula we know that time period of the pendulum is independent of the amplitude of the motion of the time period

So we will say that there is no change in the time period of the motion when we increase the amplitude of the motion of the given pendulum