Question

A swan on a lake goes airborne by flapping its wings and running on top of the water. If the swan must reach a velocity of 6.00 m/s to take off, and it accelerates from rest at an average rate of 0.35 m/s2, how far will it travel before becoming airborne?

Answer 1

Answer:51.42 m

Explanation:

Given

Swan must reach a velocity of 6 m/s to take off

and it accelerates from rest at an average rate of 0.35 m/s^2

Applying equation of motion

$v^2-u^2=2as$

Where v=final velocity

u=initial velocity

s=distance covered

a=acceleration

here u=0

$(6)^2-0=2(0.35)s$

$36=2\times 0.35\times s$

s=51.42 m