Answer:
The volume of 50% alcohol used to make the mixture = 31.25 L
The volume of 10% alcohol used to make the mixture = 18.75 L
Explanation:
Let the volume of 50% alcohol used to make the mixture = x L
Let the volume of 10% alcohol used to make the mixture = y L
Total volume of the mixture = x + y = 50 L .................. (1)
For 50% alcohol:
C₁ = 50% , V₁ = x L
For 10% alcohol :
C₂ = 10% , V₂ = y L
For the resultant alcohol solution:
C₃ = 35% , V₃ = 50 L
Using
C₁V₁ + C₂V₂ = C₃V₃
50×x + 10×y = 35×50
So,
5x + y = 175 .................. (2)
Solving 1 and 2 we get,
x = 31.25 L
y = 18.75 L
