Question

How many grams of NaCl (Molecular mass 58.44 grams/mole) are required to make a 500.00 ml stock solution of 0.5M NaCl?

Answer 1

Answer : The mass of NaCl required are 14.61 grams

Explanation : Given,

Molar mass of NaCl = 58.44 g/mole

Volume of solution = 500.00 mL

Molarity of NaCl = 0.5 M = 0.5 mole/L

Molarity : It is defined as the number of moles of solute present in 1 liter of solution.

Formula used :

$Molarity=\frac{\text{Mass of NaCl}\times 1000}{\text{Molar mass of NaCl}\times \text{volume of solution in ml}}$

Now put all the given values in this formula, we get:

$0.5mole/L=\frac{\text{Mass of NaCl}\times 1000}{58.44g/mole\times 500.00ml}$

$\text{Mass of NaCl}=14.61g$

Therefore, the mass of NaCl required are 14.61 grams