The density (mass/volume) of aluminum is 2.70 x 10³ kilograms per cubic meter (kg/m³). What is the mass of an aluminum cylinder that has a volume of 1.50 m³?
a. 5.56 x 10⁻⁴ kg
b. 1.50 x 10⁻³ kg
c. 1.80 x 10³ kg
d. 4.05 x 10³ kg

Respuesta :

Answer:

d.  [tex] 4.05\times 10^3 kg[/tex]

Step-by-step explanation:

we have the following data:

density of aluminum: [tex]2,70 \times 10^3  \frac{Kg}{m^3}[/tex].

Volume of the cylinder: [tex] 1,50 m^3 [/tex]

We have the  density formula:

[tex]\mbox{density}=\frac{\mbox{mass}}{\mbox{volume}}[/tex]

So, if we solve that formula for the mass we obtain:

[tex]\mbox{mass}=\mbox{density}\times {\mbox{volume}}[/tex].

Then, replacing the values of density of aluminum and cylinder volume we have

[tex]\mbox{mass}=2,70 \times 10^3\frac{kg}{m^3}\times 1,50 m^3 [/tex]

Note that the quantities are in scientific notation. Then for the computation we first multiply in a calculator [tex]2,70\times 1,50 = 4,05[/tex], and then we note that the [tex]m^3[/tex] terms are canceled. And we do not touch the term [tex]10^3[/tex] so that the result is expressed in scientific notation.

So we have that the answer is [tex]4,05 \times 10^3 kg[/tex].  

Otras preguntas