Question

A ball leaves the ground with a horizontal velocity of 2 m/s and a vertical velocity of 10 m/s. a) What is the angle of the resultant vector with respect to the ground?b) What is the magnitude of the resultant vector?

Answer 1

ANSWER:

a)Angle = 79°

b)Resultant vector = 10.2m/s

a)Use the pythagoras trigonometry ratios to obtain the angle..,

Vertical(opposite) = 10

Horizontal(adjacent) = 2

tan theta = 10/2...,where theta is representing the angle.

;theta = 79°

b) Resultant vector(R)...we use the pythagoras to calculate it,

Where our resultant vector is the hypothenus...,

R^2 = 10^2 + 2^2

R^2 = 104

Hence,

;Resultant vector = square root of 104

= 10.2 m/s