Answer:
voltage is 1.38 V
Explanation:
given data
weights = 150 gm = 0.150 kg
sensitivity = 0.5 volts/Newton
to find out
large a voltage
solution
we know here in by symmetry so here in x axis
F3 will be
F3 = 2mgcos(20)
F3 = 2(0.150)(9.8)cos20
F3 = 2.76 N
so volatge is
voltage = 2.76×sensitivity
voltage = 2.76×0.5
voltage = 1.38
so voltage is 1.38 V