Respuesta :
Answer:
1. 310 miles
2. Yes, the final value of miles for car A,B&C in both formulas is the same
Step-by-step explanation:
Using Zack method, lets assume there are m miles on car C
Car C=m miles
Car B= 30 miles more than those in car C = m+30 miles
Car A= 50 miles more that those in car B= 50+m+30= m+80 miles
Given after 1 hour of travel covers 50 miles
Car C=m-50 miles
Car B=m+30-50=m-20 miles
Car A= m+80-50 = m+30 miles
Condition
After 1 hour twice the miles covered by car A is less 70 miles , three times the miles on car C
This means
2(30+m) + 70 = 3(m-50)-------------------solve for m
60+2m+70=3m-150
130+2m=3m-150
130+150=3m-2m
280=m
Answers
Initial number of miles in ;
Car A=m+80 = 280+80= 360 miles
Car B= m+30 = 280+30=310 miles
Car C= m= 280 miles
Using Alexa formula
Initial
Car A=m+50 miles
Car B= m miles
Car C= m-30 miles
After 1 hour, subtract 50 miles from each car
Car A= m+50-50 = m miles
Car B= m-50 miles
Car C= m-30-50= m-80 miles
Condition
Twice the number of miles on Car A is 70 miles less than three times the number of miles on car C
2m+70=3(m-80)
2m+70=3m-240
70+240=3m-2m
310=m
Answers
Initial;
Car A=m+50=310+50=360 miles
Car B=m= 310 miles
Car C= m-30 =310-30=280 miles
Conclusion
Zack's answer will be the same as Alexa's answers.Changing the position of the variable m doesnot affect final results of miles in the cars.