Question

On a windless day, two identical balls P and Q are dropped from the top and the middle of a tower at exactly the same time as shown .Which will be more: the time taken by P to reach the middle of the tower ,or the time taken by Q to reach the ground?

Answer 1

Answer: time is the same

Explanation: the distance(H) is the same in each case .

we drop the balls , no drag force using basic kimnematics

y =gt*t/2  , yo=0 , vo=0 , y=H  , so : t= sqrt(2H/g)

comment: if distance H starts to grow....we could begin to note a difference  because of gravity g is smaller as we go up

Answer 2

Same time will be taken in both the cases

What are newton's kinematics equation  ?

The newton's kinematic equations are a set of equations that describe the motion of an object with constant acceleration

Using newton's kinematic equation

s = ut + 1/2 g $t^{2}$

u=0

t = $\sqrt{2s/g}$

let height of tower = h

t1 (time taken by P to reach the middle of the tower) = $\sqrt{(2* (h/2))/g}$

                                                                                       = $\sqrt{h/g}$

t2 (time taken by Q to reach the ground) =  $\sqrt{(2* (h/2))/g}$

                                                                      = $\sqrt{h/g}$

t1 = t2

hence same time will be taken in both the cases

learn more about newton's kinematic equation

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