Question

In 1990 Walter Arfeuille of Belgium lifted a 281.5-kg object through a distance of 17.1 cm using only his teeth. (a) How much work did Arfeuille do on the object?

Answer 1

Answer:

Work done, W = 471.73 Joules

Explanation:

It is given that,

Mass of an object, m = 281.5 kg

Distance covered by the object, d = 17.1 cm = 0.171 m

We need to find the work done by Arfeuille on the object. The work done is given by :

$W=F\times d$

$W=m\times g\times d$  

$W=281.5\times 9.8\times 0.171$  

W = 471.73 J

So, the work done by Arfeuille on the object is 471.73 Joules. Hence, this is the required solution.