A jetliner, traveling northward, is landing with a speed of 69 m/s. Once the jet touches down, it has 750 m of runway in which to reduce its speed to 6.1 m/s. Compute the average acceleration (magnitude and direction) of the plane during landing.

Respuesta :

Answer:

Acceleration, [tex]a=-3.14\ m/s^2[/tex]

Explanation:

It is given that,

Initial speed of the jetliner, u = 69 m/s

Final speed of the jetliner, v = 6.1 m/s

Distance covered, s = 750 m

We need to find the average acceleration of the jetliner. It can be calculated using third equation of motion as :

[tex]a=\dfrac{v^2-u^2}{2s}[/tex]

[tex]a=\dfrac{(6.1)^2-(69)^2}{2\times 750}[/tex]          

[tex]a=-3.14\ m/s^2[/tex]

So, the average acceleration of the plane during landing is [tex]-3.14\ m/s^2[/tex]. Hence, this is the required solution.