Answer:
Acceleration, [tex]a=-3.14\ m/s^2[/tex]
Explanation:
It is given that,
Initial speed of the jetliner, u = 69 m/s
Final speed of the jetliner, v = 6.1 m/s
Distance covered, s = 750 m
We need to find the average acceleration of the jetliner. It can be calculated using third equation of motion as :
[tex]a=\dfrac{v^2-u^2}{2s}[/tex]
[tex]a=\dfrac{(6.1)^2-(69)^2}{2\times 750}[/tex]
[tex]a=-3.14\ m/s^2[/tex]
So, the average acceleration of the plane during landing is [tex]-3.14\ m/s^2[/tex]. Hence, this is the required solution.