Question

In a Cavendish experiment that first measured gravity, a 0.730 kg lead ball was placed 0.230 m away from a 158 kg lead ball. How much gravitational force did that create?

Answer 1

Answer: $1.45(10)^{-7} N$

Explanation:

According to Newton's law of Gravitation, the force $F$ exerted between two bodies of masses $m1$ and $m2$  and separated by a distance $r$  is equal to the product of their masses and inversely proportional to the square of the distance:

$F=G\frac{(m1)(m2)}{r^2}$

Where:

$G=6.674x10^{-11}\frac{m^{3}}{kgs^{2}}$is the gravitational constant, which was thanks to Cavendish experiment

$m1=0.730 kg$

$m2=158 kg$

$r=0.230 m$

$F=6.674x10^{-11}\frac{m^{3}}{kgs^{2}}\frac{(0.730 kg)(158 kg)}{(0.230 m)^2}$

Solving:

$F=0.000000145 N= 1.45(10)^{-7} N$

Answer 2

Answer:

Coefficient: 1.45 (enter the answer in proper scientific notation)

Exponent: -7

Explanation:

Coefficient must be between 1 and 10