Question

fill in the space to make the equation true 3y5*__y—=12y2

Answer 1

Answer:

The second blank, which is the exponent on the y there, is -3.

$3y^5 \cdot 4y^{-3}$

Step-by-step explanation:

$3(?)=12$ implies $?=4$ since 3(4)=12.

$y^5 \cdot y^{?}=y^{5+?}=y^{2}$ implies $5+?=2$.

$5+?=2$ can be solved by subtracting 5 on both sides. This gives you:

$?=2-5$

$?=-3$

Let's put it altogether:

$3y^5 \cdot 4y^{-3}$

$12y^{5+(-3)}$

$12y^{2}$

So the first blank is 4.

The second blank, which is the exponent on the y there, is -3.