Give the values of ΔHo, ΔSo, and T, determine ΔGo and indicate if the reaction is spontaneous. ΔHo = 115 kJ , ΔSo = 263 J/K , and T = 615K ΔGo=___ kJ Spontaneous? yes or no

Respuesta :

Answer:

[tex]\Delta G^0=-46.745\ kJ[/tex]

[tex]\Delta G^0<0[/tex], the reaction is spontaneous.

Explanation:

The expression for the standard change in free energy is:

[tex]\Delta G^0=\Delta H^0-T\times \Delta S^0[/tex]

Given that:

[tex]\Delta H^0=115\ kJ[/tex]

[tex]T=615\ K[/tex]

[tex]\Delta S^0=263\ J/K[/tex]

Also, 1 J = 10⁻³ kJ

So,

[tex]\Delta S^0=0.263\ kJ/K[/tex]

Applying in the above formula as:

[tex]\Delta G^0=115-615\times 0.263\ kJ[/tex]

[tex]\Delta G^0=-46.745\ kJ[/tex]

Since, [tex]\Delta G^0<0[/tex], the reaction is spontaneous.