Answer:
[tex]\Delta G^0=-46.745\ kJ[/tex]
[tex]\Delta G^0<0[/tex], the reaction is spontaneous.
Explanation:
The expression for the standard change in free energy is:
[tex]\Delta G^0=\Delta H^0-T\times \Delta S^0[/tex]
Given that:
[tex]\Delta H^0=115\ kJ[/tex]
[tex]T=615\ K[/tex]
[tex]\Delta S^0=263\ J/K[/tex]
Also, 1 J = 10⁻³ kJ
So,
[tex]\Delta S^0=0.263\ kJ/K[/tex]
Applying in the above formula as:
[tex]\Delta G^0=115-615\times 0.263\ kJ[/tex]
[tex]\Delta G^0=-46.745\ kJ[/tex]
Since, [tex]\Delta G^0<0[/tex], the reaction is spontaneous.