Answer:
Q = 29.4 x 10⁻⁹ C.
Explanation:
Electric field due to a charge Q at distance d is given by coulomb law as follows
Electric field
E = k Q /d²
where for air k which is a constant is 9 x 10⁹
[tex]E=\frac{k\times Q}{d^2}[/tex]
Given E = 32.08 , d = 2.84 m
Putting these values in the relation above, we have
[tex][tex]32.08=\frac{9\times 10^9\times Q}{(2.84)^2}[/tex][/tex]
Q = 29.4 x 10⁻⁹ C.