Respuesta :
Answer:570 N
Explanation:
Given
one rope applies a force of 475 N in west direction
other applies a force of 315 N in south direction
So both forces are at an angle of [tex]90^{\circ}[/tex]
Net resultant of two forces is
[tex]R=\sqrt{315^2+475^2}[/tex]
[tex]R=\sqrt{99225+225625}[/tex]
[tex]R=569.95 N \approx 570[/tex]
and the resultant will be an angle of \theta with 475 Newton force
[tex]Rcos\theta =475[/tex]
[tex]cos\theta =\frac{475}{569.95}=0.833[/tex]
[tex]\theta =cos^{-1}(0.833)=33.591[/tex]
So replacing two force we can apply a force of magnitude of 570 N at angle of [tex]33.6 ^{\circ}[/tex] with west
The magnitude of the resultant force acting on ropes is 570 N and it acts at angle of 33.6 degrees relative to due west direction.
What is force?
Force is the effect of pull or push due to which the object having a mass changes its velocity.
The force is of two types-
- Push-When the force applied in the direction of motion of the object, then the force is called the push force.
- Pull- When the force applied in the opposite direction of motion of the object, then the force is called the pull force.
As one rope applies a force of 475 newtons in a direction due west and the other applies a force of 315 newtons in a direction due south.
Thus, the net force of the two ropes can be given as,
[tex]F=\sqrt{475^2+315^2}\\F\cong570\rm N[/tex]
Now this resultant will be at the south-west direction. Let the resultant force acting on the south-west direction at an angle of [tex]\theta[/tex].
Thus, the net resultant force acting relative to due west direction will be,
[tex]F\cos\theta={475}{}\\\cos\theta=\dfrac{475}{570}\\\theta=\cos{-1}(0.833)\\\theta=33.6[/tex]
Thus, the magnitude of the resultant force acting on ropes is 570 N and it acts at angle of 33.6 degrees relative to due west direction.
Learn more about the force here;
https://brainly.com/question/388851