Question

28.5g of iron shot is added to a graduated cylinder contaning 45.50ml of water. The water level rises to the 49.10 ml mark, from this information, caculate the density of iron

Answer 1

Answer:

7.92 g/ml

Explanation:

Given that, the volume of water  in the graduated cylinder is,

$V_{w}=45.50 ml$

Volume of (water+iron shot) is,

$V_{w+Fe}=49.10 ml$

Now the volume of iron shot can be calculate as,

$V_{Fe}=V_{w+Fe}-V_{w}\\V_{Fe}=49.10 ml-45.50 ml\\V_{Fe}=3.6 ml$

And the mass of the iron shot which is given is 28.5 g.

Now the density can be calculated as,

$D=\frac{m}{V}$

Here, m is the mass, V is the volume

Now,

$D=\frac{28.5}{3.6}\\D=7.92 gm/ml$

Therefore, the density of iron is 7.92 g/ml.