Question

What is the MINIMUM capacity, in kW, required to heat 1,000 cfm (472 L/s) from 65°F (18.3°C) to 95°F (35.0°C)? A. 2 B. 10 C. 20

Answer 1

Answer:

B.10Kw

Explanation:

use this formula

Q=V*ρ*Cp*(T2-T1)

Q=power

V=volume flow

ρ=density                  for air ρ=1.225kg/m^3

Cp=especific heat             for air  Cp=1.005 KJ/(kgK)

T2=final temperature

T1=initial temperature

Q=0.472*1.225*1.005(35-18.3)=9.7Kw≈10Kw

Answer 2

B. would be the correct answer, let me know if im wrong