Question

Write the equation of a line containing the point (-4, 6) and parallel to 3x - 2y =8.

Answer 1

3x -2y=8
Y= 3/2 x- 4
Hence slope is 3/2
The line d (for example) is parallel to this line the slope of d = slope of this line = 3\2
Then equation of d : y =3/2 x - b
The point (-4,6) belongs to d
Y - 6 = 3/2 (x +4)
Y= 3/2 x + 6 +6
Y= 3/2x +12


Then the equation is : Y= 3/2x +12

Answer 2

The answer is 3x + 2y - 8 += 0