Answer:
226.2 m/sec
Explanation:
We have given [tex]\Delta x=510nm=510\times 106{-9}m[/tex]
The plank's constant [tex]h=6.67\times 10^{-34}[/tex]
Mass of electron [tex]m=9.11\times 10^{-31}kg[/tex]
Now according to Heisenberg uncertainty principle [tex]\Delta v\geq \frac{h}{2\pi m\Delta x}[/tex]
So [tex]\Delta v\geq \frac{6.6\times 10^{-34}}{2\times 3.14\times 9.11\times 10^{-31}\times 510\times 10^{-9}}=226.2m/sec[/tex]