Question

Write the standard form of the equation of the line passing through the point (-2, 3) and perpendicular to the line
4x - 3y = -9.

Answer 1

Answer:

y + 3/4x = 6/4

Step-by-step explanation:

1. Find slope of first line:

-3y = -4x - 9

y = 4/3 x - 9

slope 1 = 4/3

2. Find slope of the second line:

perpendicular = flip the slope and multiply by -1 (negative inverse)

slope 2 = - 3/4

3. Plug into standard form formula:

$y - y_{1}  = m(x -x_{1})$

$y_{1} = 3\\ x_{1} = -2\\ m = -\frac{3}{4}$

y - 3 = -3/4(x - (-2))

y - 3 = -3/4x - 6/4

y = -3/4x + 6/4

y + 3/4x = 6/4