Respuesta :
Answer: The percent gallium in gallium bromide is 30.30 %.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of gallium bromide = 0.165 g
Molar mass of titanium gallium bromide = 229.53 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of gallium bromide}=\frac{0.165g}{229.53g/mol}=0.00072mol[/tex]
- The chemical equation for the reaction of gallium bromide and silver nitrate follows:
[tex]GaBr_2+2AgNO_3\rightarrow 2AgBr(s)+Ga(NO_3)_2[/tex]
By Stoichiometry of the reaction:
1 moles of gallium bromide produces 1 mole of gallium nitrate
So, 0.00072 moles of gallium bromide will produce = [tex]\frac{1}{1}\times 0.00072=0.00072moles[/tex] of gallium nitrate
- Now, calculating the mass of gallium nitrate from equation 1, we get:
Molar mass of gallium nitrate = 193.73 g/mol
Moles of gallium nitrate = 0.00072 moles
Putting values in equation 1, we get:
[tex]0.00072mol=\frac{\text{Mass of gallium nitrate}}{193.73g/mol}\\\\\text{Mass of gallium nitrate}=0.139g[/tex]
Calculating the mass of gallium in the reaction, we use unitary method:
In 1 mole of gallium nitrate, 1 mole of gallium atom is present.
In 193.73 grams of gallium nitrate, 69.72 g of gallium atom is present.
So, in 0.139 grams of gallium nitrate, the mass of gallium present will be = [tex]\frac{69.72}{193.73}\times 0.139=g[/tex]
- To calculate the percentage composition of gallium in gallium bromide, we use the equation:
[tex]\%\text{ composition of gallium}=\frac{\text{Mass of gallium}}{\text{Mass of gallium bromide}}\times 100[/tex]
Mass of gallium bromide = 0.165 g
Mass of gallium = 0.050 g
Putting values in above equation, we get:
[tex]\%\text{ composition of gallium}=\frac{0.050g}{0.165g}\times 100=30.30\%[/tex]
Hence, the percent gallium in gallium bromide is 30.30 %.
