Answer : The volume of solution will be, [tex]7.047\times 10^6L[/tex]
Explanation : Given,
Mass of AgO = 900 mg = 900000 g
conversion used : (1 mg = 1000 g)
Molar mass of AgO = 124 g/mole
Molarity of AgO = [tex]1.03\times 10^{-6}mM=0.00103M[/tex]
Molarity : It is defined as the number of moles of solute present in one liter of solution.
Formula used :
[tex]\text{Molarity}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{volume of solution in liter}}[/tex]
Now put all the given values in this formula, we get the active mass of urea.
[tex]0.00103M=\frac{900000g}{124g/mole\times \text{volume of solution in liter}}[/tex]
[tex]\text{volume of solution in liter}=7046664.579L=7.047\times 10^6L[/tex]
Therefore, the volume of solution will be, [tex]7.047\times 10^6L[/tex]
