Question

A compact car gets 37.5 miles per gallon on the highway. If gasoline contains 84.2 percent carbon by mass and has a density of 0.82059 g/mL, determine the mass of carbon dioxide produced during a 500 mile trip(3.785 litres per gallon)

Answer 1

Answer:

127,849.7891 grams of of carbon dioxide produced during a 500 mile trip.

Explanation:

Mileage of the compact car = 37.5 mile/gal

Miles covered through out the trip = 500 mile

Gallons of gasoline used up through out the trip =

= $\frac{1}{37.5}gal/mile\times 500 mile=13.333 gallons=50.465 L$

(1 gal = 3.785 L) given

Density of the gasoline =d=  0.82059 g/L

Mass of the gasoline = m

Volume of the gasoline ,V = 50.465 L = 50,465 mL

$m= d\times = 0.82059 g/L\times 50,465 mL=41,411.074 g$

Mass percentage of carbon = 84.2%

Mass of carbon in 41,411.074 g of gasoline be x.

$84.2\%=\frac{x}{41,411.074 g}\times 100$

x = 34,868.1243 g

$C+O_2\rightarrow CO_2$

Moles of carbon = $\frac{34,868.1243 g}{12 g/mol}=2905.6770 mol$

According to reaction , 1 mol carbon gives 1 mole of carbon dioxide.

Then 2905.6770 moles of carbon will produce:

$\frac{1}{1}\times 2905.6770 mol=2905.6770 mol$ of carbon dioxide

Mass of 2905.6770 moles of carbon dioxide:

$2905.6770 mol\times 44 g/mol=127,849.7891 g$

127,849.7891 grams of of carbon dioxide produced during a 500 mile trip.