Respuesta :

Answer: 2588 grams of ethane are there in 100 L of this gas at 80 degree celsius and 25 atm.

Explanation:

According to the ideal gas equation:'

[tex]PV=nRT[/tex]

P = Pressure of the gas = 25 atm    

V= Volume of the gas = 100 L

T= Temperature of the gas = 80°C = (80+273)K=353 K       (0°C = 273 K)

R= Gas constant = 0.0821 atmL/K mol

n=  moles of gas= ?

[tex]n=\frac{PV}{RT}=\frac{25\times 100}{0.0821\times 353}=86.3moles[/tex]

Mass of gas=[tex]moles\times {molar mass}}=86.3\times 30=2588g[/tex]

Thus 2588 grams of ethane are there in 100 L of this gas at 80 degree celsius and 25 atm.