Question

swer all parts. (a) What is the wavelength (in nm) of radiation that has an energy ...
Be sure to answer all parts.

(a) What is the wavelength (in nm) of radiation that has an energy content of 3.55 × 103 kJ/mol?


__× 10__ nm

(b) In which region of the electromagnetic spectrum is this radiation found?


gamma ray


visible


radio wave


microwave


X-ray


ultraviolet


infrared

Answer 1

Answer:

a) The wavelength is around 33.8 nm = 3.38*10⁻¹ nm

b) Ultraviolet

Explanation:

a) The energy (E) of a photon is related to its wavelength (λ) by the Planck's equation:

$E = h\frac{c}{\lambda}----(1)$

where h = Planck's constant = 6.626*10^-34 Js

c = speed of light = 3*10^8 m/s

E = 3.55*10^6 J/mol

The energy in terms of J/photon is:

$=\frac{3.55*10^{6} J/mol*1mol}{6.023*10^{23} photons } =5.89*10^{-18} J/photon$

Based on eq(1)

\lambda = h\frac{c}{E}=6.626*10^{-34}Js*\frac{3*10^{8}m/s}{5.89*10^{-18}J}=3.38*10^{-8}m

The wavelength is around 33.8 nm = 3.38*10⁻¹ nm

b) In the electromagnetic spectrum the ultraviolet range extends from 390 nm-8.82 nm

The calculated wavelength of 33.8 nm should fall in the UV range.