Answer:
The required positive two digit integer is 32.
Step-by-step explanation:
Given : If k is a positive two-digit integer.
1) The sum of the tens digit of k and the units digit of k is 5.
2) The tens digit of k + 6 is 3.
To find : What is the tens digit of k ?
Solution :
Let the two digit integer be [tex]10a+b[/tex]
According to question,
By 1, The sum of the tens digit of k and the units digit of k is 5.
i.e. [tex]a+b=5[/tex]
The possible cases from counting are,
14, 41, 23, 32, 50 whose sum is 5.
By 2, The tens digit of k + 6 is 3.
Which means take number which is added by 6 and give tens digit as 3.
The only possible case is when k=32
As 32+6=38 where tens digit is 3.
Therefore, The required positive two digit integer is 32.
