Question

In Canada and the United Kingdom, devices that measure blood glucose levels provider reading to millimoles per litre. If
measurement of 5.3mM is observed, what is the concentration of glucose (C6H12O6) mg/dL?

Answer 1

Answer:

The concentration of glucose 95.4 mg/dL:

Explanation:

$Molarity = 1000 \times \text{milliMolarity}$

Concentration of glucose in blood = 5.3 milli Molar

This means that 5.3 milli moles are present in 1 l of solution.

5.3 milli moles = 0.0053 moles

So, from this we can say that  0.0053 moles of glucose are present in 1 L solution.

Mass of 0.0053 moles of glucose :

= 0.0053 mol × 180 g/mol = 0.954 g

(1 g = 1000 mg)

0.954 g = 954 mg

945 milli grams in 1 liter of the solution.

(1 L = 10 dL)

The concentration of glucose in mg/dL:

$\frac{945 mg}{10 dL}=94.5 mg/dL$