Answer:
So height on moon = 2 × height on mars
So option (a) will be correct answer
Explanation:
We have given the [tex]g_{mars}=2g_{moon}[/tex]
[tex]g_1=2g_2[/tex]
We know that energy of any object is always conserved
Let the object is falling downward, when the object heats the ground its kinetic energy will be changed in potential energy
Let [tex]v_1\ and\ g_1\ for\ mars\ and\ v_2\ and\ g_2\ for\ moon[/tex]
So [tex]\frac{1}{2}mv_1^2=mg_1h_1[/tex]
[tex]v_1^2=2g_1h_1[/tex]
For moon [tex]v_2^2=2g_2h_2[/tex]
We have given that speed is same on both mars and moon
So [tex]v_1=v_2[/tex]
[tex]v_1^2=v_2^2[/tex]
[tex]2g_1h_1=2g_2h_2[/tex]
[tex]2\times 2g_2h_1=2g_2h_2[/tex]
[tex]h_2=2h_1[/tex]
So height on moon = 2 × height on mars
So option (a) will be correct answer