Answer:
A. 0.3085
B. 0.3829
C. 0.1056
D. 0.0122. Yes, "very preterm" babies are unusual.
Step-by-step explanation:
A random variable X distributed approximately normal with mean mu = 271 and standard deviation sigma = 8, can be standardized by the transformation Z = (X - mu) / sigma. In this way:
For X = 275 you have Z = (275 - 271) / 8 = 0.5
For X = 267 you have Z = (267 - 271) / 8 = -0.5
For X = 273 you have Z = (273 - 271) / 8 = 0.25
For X = 261 you have Z = (261 - 271) / 8 = -1.25
For X = 253 you have Z = (253 - 271) / 8 = -2.25
A. P (X> 275) = P (Z> 0.5) = 0.3085
B. P (267 <X <275) = P (-0.5 <Z <0.5) = 0.3829
C. P (X <= 261) = P (Z <= -1.25) = 0.1056
D. P (X <= 253) = P (Z <= -2.25) = 0.0122. Yes, "very preterm" babies are unusual.