Answer:
The diameter of the hose is 0.326 mm.
Explanation:
Given that,
Speed of car = 28 miles/galllon
We need to calculate the radius
The rate of flow of fluid is from the equation of continuity
[tex]\dfrac{V}{t}=Av[/tex]
Where, A = area of cross sectional
[tex]\dfrac{V}{t}=\pi r^2v[/tex]
We know that,
The velocity is the ratio of displacement of gas per unit time.
[tex]\dfrac{V}{t}=\pi r^\dfrac{x}{t}[/tex]
[tex]\dfrac{V}{x}=\pi r^2[/tex]
Put the value into the formula
[tex]\dfrac{0.00378541}{28\times1609.34}=\pi r^2[/tex]
[tex]r=\sqrt{\dfrac{0.00378541}{28\times1609.34\times\pi}}[/tex]
[tex]r=1.63\times10^{-4}\ m[/tex]
We need to calculate the diameter of the hose
[tex]d = 2r[/tex]
Put the value of r
[tex]d=2\times1.63\times10^{-4}[/tex]
[tex]d=0.326\ mm[/tex]
Hence, The diameter of the hose is 0.326 mm.