calculate the empirical for the molecular formula mass and the molar mass of each of the following minerals:
(a) Limestone, CaCO3
(b)halite, NaCl
(c)beryl, Be3Al2Si6O18
(d)malachite, Cu2(OH)2CO3
(e)turquoise, CuAl6(PO4)4(OH)8(H2O)4

Respuesta :

Explanation:

Molar mass  

The mass present in one mole of a specific species .

The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .

(a) Limestone, CaCO₃

Molar mass of  the atoms are -

Calcium , Ca = 40 g / mol

Carbon , C = 12 g/mol

Oxygen , O = 16 g/mol

Molecular mass of CaCO₃ = (40 g / mol ) + (  12 g/mol ) + ( 3 * 16 g/mol ) = 100 g/mol.

(b) halite, NaCl

Molar mass of the atoms are -

Sodium , Na = 23 g/mol

Chlorine , Cl = 35.5

Molecular mass of NaCl = 23 + 35.5 = 58.5 g/mol .

(c) beryl,  Be₃Al₂Si₆O₁₈

Molar mass of the atoms are -

Beryllium , Be = 9 g/mol

Aluminum , Al = 27 g/mol

Silicon , Si = 28 g/mol

Oxygen , O = 16 g/mol

Molecular mass of Be₃Al₂Si₆O₁₈ = ( 3* 9 ) + ( 2*27 ) + ( 6 * 28 ) + ( 18 * 16 ) =  537 g/mol .

(d) malachite, Cu₂(OH)₂CO₃

Molar mass of the atoms are -

Copper , Cu = 63.5 g/mol

Oxygen , O = 16 g/mol

Carbon , C = 12 g/mol

hydrogen , H = 1 g /mol

Molecular mass of Cu₂(OH)₂CO₃ = ( 2 * 63.5 ) + ( 5 * 16 ) + ( 2 * 1 ) + ( 1* 12 ) = 221 g/mol.

(e) turquoise, CuAl₆(PO₄)₄(OH)₈(H₂O)₄

Copper , Cu = 63.5 g/mol

Aluminum , Al = 27 g/mol

Phosphorous , P = 31 g/mol

Oxygen , O = 16 g/mol

hydrogen , H = 1 g /mol

Molecular mass of CuAl₆(PO₄)₄(OH)₈(H₂O)₄ =

( 63.5*1) + (6 *27) + (4* 31 ) + (28 *16 ) + ( 16 *1 ) = 813 g/mol.