Question

The perimeter of a rectangle is P= 2L +2W, where L is the length and W is the width. If the perimeter is 200 feet and the length is 40 feet more than the width, what are the dimensions?

Answer 1

Answer:

Length - 70

Width - 30

Step-by-step explanation:

Let the width be x

Length is 40 more than width which makes length = x + 40

Perimeter = 2L + 2W

2(x + 40) + 2(x)

Open brackets

2x + 80 + 2x = 4x + 80

Perimeter = 200

200 = 4x + 80

4x = 200 - 80

4x = 120

x = 120/4

x = 30

Width = 30

Length = x + 40 = 70

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