Answer:
452.49 rev/min
Step-by-step explanation:
The circumference of the wheel is pi times the diameter. The rest is units conversion.
[tex]35\dfrac{mi}{h}=\dfrac{35\,mi}{1\,h}\cdot\dfrac{1\,h}{60\,min}\cdot\dfrac{5280\,ft}{1\,mi}\cdot\dfrac{12\,in}{1\,ft}\cdot\dfrac{1\,rev}{26\pi\,in}\\\\=\dfrac{35\cdot 5280\cdot 12}{60\cdot 26\pi}\cdot\dfrac{rev}{min}\approx\dfrac{452.49\,rev}{min}[/tex]
