Respuesta :

Answer:

[tex]2a(2a-3b)[/tex]

Step-by-step explanation:

4 and 6 have a common factor 2.

[tex]a^2[/tex] and [tex]ab[/tex] have a common factor [tex]a[/tex].

So we can factor out [tex]2a[/tex]:

[tex]4a^2-6ab[/tex]

[tex]2a(\frac{4a^2}{2a}-\frac{6ab}{2a})[/tex]

[tex]2a(\frac{2a(2a)}{2a}-\frac{3b(2a)}{2a})[/tex]

[tex]2a(2a-3b)[/tex]

4a^2-6ab
=(2a)^2-6ab

by completing the square

=(2a)^2-(2*2a*3b/2)+(3b/2)^2-(3b/2)^2

=(2a-3b/2)^2-(3b/2)^2
=(2a-3b/2+3b/2)(2a-3b/2-3b/2)
{Since a^2-b^2= (a-b)(a+b)}
=(2a)(2a-3b) (Ans)
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