Respuesta :
Answer:
[tex]2a(2a-3b)[/tex]
Step-by-step explanation:
4 and 6 have a common factor 2.
[tex]a^2[/tex] and [tex]ab[/tex] have a common factor [tex]a[/tex].
So we can factor out [tex]2a[/tex]:
[tex]4a^2-6ab[/tex]
[tex]2a(\frac{4a^2}{2a}-\frac{6ab}{2a})[/tex]
[tex]2a(\frac{2a(2a)}{2a}-\frac{3b(2a)}{2a})[/tex]
[tex]2a(2a-3b)[/tex]
4a^2-6ab
=(2a)^2-6ab
by completing the square
=(2a)^2-(2*2a*3b/2)+(3b/2)^2-(3b/2)^2
=(2a-3b/2)^2-(3b/2)^2
=(2a-3b/2+3b/2)(2a-3b/2-3b/2)
{Since a^2-b^2= (a-b)(a+b)}
=(2a)(2a-3b) (Ans)
=(2a)^2-6ab
by completing the square
=(2a)^2-(2*2a*3b/2)+(3b/2)^2-(3b/2)^2
=(2a-3b/2)^2-(3b/2)^2
=(2a-3b/2+3b/2)(2a-3b/2-3b/2)
{Since a^2-b^2= (a-b)(a+b)}
=(2a)(2a-3b) (Ans)