Respuesta :
- The parabola is a flat curve that is Spiegler and about U-shaped.
- It corresponds to numerous superficial mathematical descriptions, all of which can be shown to define exactly the same curves.
- A parabola is described by the point (focus) as well as an axis (the directrix).
Given:
[tex]\to \bold{ f(x)=-4x^2}\\\\Let\\\\\to \bold{y=f(x)}\\\\\therefore \ \ \\\to \bold{y=-4x^2}\\\\\to \bold{ x^2=-\frc{1}{4}y}\\\\[/tex]
Equation of parabola:
[tex]\to \bold{\text{domain=real number}}\\\\\to \bold{\text{range=}( \infty ,0)}}[/tex]
is decreasing over [tex]\bold{(0, \infty)}[/tex]and increasing over [tex]\bold{(-\infty,0)}[/tex].
[tex]\to \bold{(0,0)}[/tex] is a maximum these are only one x-intercept at [tex]\bold{ x=0}[/tex]
Therefore, the final answer "Option A and Option D".
Learn more:
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A function can be represented as a graph which shows its characteristics
The true statements about the function f(x) = -4·x² are;
- The domain is {x | x is a real number}
- The point (0, 0) is a maximum
The reason the above option are correct as follows:
The given function is presented as follows;
f(x) = -4·x²
Given that the operation in the function is the raising of the power of x to two, followed by multiplication by '-4', which are operations defined for all real numbers, the function can take all real numbers as input
Therefore;
- The domain is {x | x is a real number}
The 'x²' in the function f(x) always gives a positive value, therefore, -4·x² is always negative, except for the point x = 0, where, -4 × 0² = 0 = f(0)
Therefore, f(x) = -4·x² is 0, when x = 0, which is the only nonnegative value and therefore, the maximum point, and the only x and y intercept
Therefore;
- The point (0, 0) is a maximum
The function is increasing in the domain (-∞, 0]
The range of the function is (-∞, 0]
Therefore, two true statements are;
A) The domain is {x | x is a real number}
D) The point (0, 0) is a maximum
Learn more about properties of the graph of a function here:
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