Answer:
E = 1.51 × 10²¹ J
Explanation:
Given:
Rest mass of the spaceship, m = 120 metric tonn = 120 × 10³ kg
Speed, v = 0.481 c
Now,
the relativistic kinetic energy required is calculated as:
[tex]E=\frac{mc^2}{\sqrt{1-\frac{v^2}{c^2}}}-mc^2[/tex]
where, c is the speed of the light = 3 × 10⁸ m/s
on substituting the respective values, we get
[tex]E=\frac{120\times10^3\times{c^2}}{\sqrt{1-\frac{(0.481c)^2}{c^2}}}-(120\times10^3\times{c^2})[/tex]
or
E = 1.51 × 10²¹ J
