Answer:
Step-by-step explanation:
Given that a variable follows a standard normal distribution
Z is N(0,1)
Thus we can use the standard normal distribution table to find the required probabilities or c
a) [tex]P(z > -0.86)[/tex]
We know std normal is symmetric about 0. Hence this prob is area from 0 to end on right side and 0 to 0.86 on left side
= sum of two prob = 0.3051+0.5=0.8051
b) [tex]P(z > c) = 0.3338[/tex]
Since prob is less than 0.5 we find that c lies to the right of 0. i.e.c is positive
Between 0 and c prob [tex]= 0.5-0.3338 = 0.1662[/tex]
Seeing the table we find that c = 0.43