Respuesta :
Answer:
effective dose is 1.2 mrem
Explanation:
given data
mass m = 70 kg
absorb n = 4.5 × [tex]10^{8}[/tex]
energy = 1.2 MeV
neutrons = 10
to find out
equivalent dosage
solution
we know here total energy in a day is
total energy = 4.5 × [tex]10^{8}[/tex] × 1.2
total energy = 5.4 × [tex]10^{14}[/tex] eV
and total energy = 5.4 × [tex]10^{14}[/tex] × 1.6 × [tex]10^{-19}[/tex]
so total energy = 8.64 × [tex]10^{-5}[/tex] J
and for mass 70 kg
it will be = 8.64 × [tex]10^{-5}[/tex] / 70
= 1.23 × [tex]10^{-4}[/tex] rad
so
effective dose is here = 1.23 × [tex]10^{-4}[/tex] × 10 = 0.0012 rem
so effective dose is 1.2 mrem
The equivalent dosage of the radiation exposure for this researcher is 1.23 × 10-7millirem.
HOW TO CALCULATE EQUIVALENT DOSAGE?
According to this question, a 70-kg researcher absorbs 4.5 x 10^8 neutrons in a workday, each of energy 1.2 MeV.
- mass = 70 kg
- absorb n = 4.5 × 10⁸
- Energy = 1.2 MeV
- neutrons = 10
To find out equivalent dosage;
The total energy in a day can be calculated as follows:
Total energy = 4.5 × 10⁸ × 1.2 = 5.4 × 10⁸
5.4 × 10⁸ × 1.6 × 10-¹⁹
= 8.64 × 10-¹¹
For a mass of 70kg, 8.64 × 10-¹¹ ÷ 70
= 1.23 × 10-¹⁰
Therefore, the equivalent dosage of the radiation exposure for this researcher is 1.23 × 10-7millirem.
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