Answer:
[tex]n=1.63\times 10^{-35}\ particles[/tex]
Explanation:
It is given that,
Pressure in the intergalactic space, [tex]P=3.68\times 10^{-28}\ Pa[/tex]
Temperature, T = 2.7 K
Volume, [tex]V=1\ cm^3=10^{-6}\ m^3[/tex]
We need to find the number of particles. The formula for the number of molecules in air is given by :
[tex]PV=nRT[/tex], R is gas constant
[tex]n=\dfrac{PV}{RT}[/tex]
[tex]n=\dfrac{3.68\times 10^{-28}\times 10^{-6}}{8.314\times 2.7}[/tex]
[tex]n=1.63\times 10^{-35}\ particles[/tex]
So, the number of particles in intergalactic space is [tex]1.63\times 10^{-35}\ particles[/tex]. Hence, this is the required solution.