Question

A fish is 1.0 m below the surface of a lake. How far below the surface of the lake will the fish appear to be when viewed directly from above at normal incidence ?

Answer 1

Answer:

0.752 m

Explanation:

μ = Refractive index of water = 1.33

Real depth = 1 m

$\mu=\frac{\text{Real depth}}{\text{Apparent depth}}\\\Rightarrow \text{Apparent depth}=\frac{\text{Real depth}}{\mu}\\\Rightarrow \text{Apparent depth}=\frac{1}{1.33}\\\Rightarrow \text{Apparent depth}=0.752\ m$

∴ The fish will appear 0.752 m below the surface of the lake.