Answer:
[tex]y=\frac{-3}{5}x+3[/tex]
I don't see this in any of your choices.
Please be sure the problem and choices are as you want them to be seen by others. Thanks kindly.
I do hope my answer is helpful.
Step-by-step explanation:
[tex]3x+5y=15[/tex]
We want to get the term that contains [tex]y[/tex] by itself.
This means we want to get [tex]5y[/tex] by itself first.
To do this I need to get rid of the plus [tex]3x[/tex] on that side.
I will do the inverse operation of that; I will subtract 3x on both sides.
[tex]3x+5y=15[/tex]
-3x -3x
[tex]5y=15-3x[/tex]
[tex]5y=+15-3x[/tex]
[tex]5y=-3x+15[/tex] since addition is commutative.
Now we have the 5y term by itself. We want the factor y in 5y by itself.
To undo multiplication you must divide. We will divide both sides by 5:
[tex]5y=-3x+15[/tex]
------------------------------
5
[tex]\frac{5y}{5}=\frac{-3x+15}{5}[/tex]
[tex]y=\frac{-3x}{5}+\frac{15}{5}[/tex]
[tex]y=\frac{-3}{5}x+3[/tex]