Question

Calculate the magnitude of the force on an electron moving at 1.1x10^6 m/s at an angle of 5.8 degrees to a magnetic field of 0.6 Tesla. Give your answer in Newtons.

Answer 1

Answer:

The force on electron is $106.715\times 10^{-16}$Newtons

Explanation:

The force on a moving charge in a magnetic field is given by

$\overrightarrow{F}=q\overrightarrow{v}\times \overrightarrow{B}\\\\=|F|=q|v||B|sin(\theta )$

Applying the given values we get

$F=1.6\times 10^{-19}\times 1.1\times 10^{6}\times 0.6\times sin(5.8)\\\\\therefore F=106.715\times 10^{-16}Newtons$