Answer:
In order to maximize the profit, should be produced 200 software program and 235 video games per week
Step-by-step explanation:
Let
x ------> the number of software program
y -----> the number of video games
we know that
[tex]x \leq 200[/tex] -----> inequality A
[tex]y \leq 300[/tex] -----> inequality B
[tex]x+y \leq 435[/tex] -----> inequality C
Using a graphing tool
The solution is the shaded area between the positive values fo x and y
see the attached figure
The vertices of the shaded area are
(0,0),(0,300),(135,300),(200,235),(200,0)
The profit function is equal to
[tex]P=50x+35y[/tex]
Substitute the value of x and the value of y of each vertices in the profit function
For (0,300) ----- [tex]P=50(0)+35(300)=\$10,500[/tex]
For (135,300) ----- [tex]P=50(135)+35(300)=\$17,250[/tex]
For (200,235) ----- [tex]P=50(200)+35(235)=\$18,225[/tex]
For (200,0) ----- [tex]P=50(200)+35(0)=\$10,000[/tex]
therefore
In order to maximize the profit, should be produced 200 software program and 235 video games per week