Question

Find the equation of a circle with a center at (-1, 5) and a point on the circle is (4, 4).

Answer 1

Answer:

$(x +1)^2+(y-5)^2=26$

Step-by-step explanation:

Use the distance formula to find the radius using the center (-1,5) and the point (4,4).

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

This implies that;

$r = \sqrt{(4 - - 1)^{2} + ( {4 - 5)}^{2} }$

$r = \sqrt{ {5}^{2} + {( - 1)}^{2} }$

$r = \sqrt{26}$

We use the formula:

$(x- - 1)^2+(y-5)^2=( \sqrt{26}) ^2$

$(x + 1)^2+(y-5)^2=26$

The required equation is

$(x + 1)^2+(y-5)^2=26$