Answer: The number of moles of ideal gas are 0.0037 moles
Explanation:
To calculate the mass of helium gas, we use the equation given by ideal gas:
PV = nRT
where,
P = Pressure of helium gas = 52 cmHg = 520 mm Hg (Conversion factor: 1 cm = 10 mm)
V = Volume of the helium gas = 137 mL = 0.137 L (Conversion factor: 1L = 1000 mL)
n = number of moles of gas = ?
R = Gas constant = [tex]62.3637\text{ L.mmHg }mol^{-1}K^{-1}[/tex]
T = Temperature of helium gas = [tex]98^oF=309.817K[/tex] (Conversion factor: [tex](T(K)-273.15)=(T(^oF)-32)\times \frac{5}{9}[/tex] )
Putting values in above equation, we get:
[tex]520mmHg\times 0.137L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 309.817K\\\\n=0.0037mol[/tex]
Hence, the number of moles of gas is 0.0037 moles.
